3.1.63 \(\int \frac {\cot ^5(c+d x)}{a+a \sec (c+d x)} \, dx\) [63]

Optimal. Leaf size=145 \[ -\frac {1}{32 a d (1-\cos (c+d x))^2}+\frac {1}{4 a d (1-\cos (c+d x))}+\frac {1}{24 a d (1+\cos (c+d x))^3}-\frac {9}{32 a d (1+\cos (c+d x))^2}+\frac {15}{16 a d (1+\cos (c+d x))}+\frac {11 \log (1-\cos (c+d x))}{32 a d}+\frac {21 \log (1+\cos (c+d x))}{32 a d} \]

[Out]

-1/32/a/d/(1-cos(d*x+c))^2+1/4/a/d/(1-cos(d*x+c))+1/24/a/d/(1+cos(d*x+c))^3-9/32/a/d/(1+cos(d*x+c))^2+15/16/a/
d/(1+cos(d*x+c))+11/32*ln(1-cos(d*x+c))/a/d+21/32*ln(1+cos(d*x+c))/a/d

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Rubi [A]
time = 0.07, antiderivative size = 145, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {3964, 90} \begin {gather*} \frac {1}{4 a d (1-\cos (c+d x))}+\frac {15}{16 a d (\cos (c+d x)+1)}-\frac {1}{32 a d (1-\cos (c+d x))^2}-\frac {9}{32 a d (\cos (c+d x)+1)^2}+\frac {1}{24 a d (\cos (c+d x)+1)^3}+\frac {11 \log (1-\cos (c+d x))}{32 a d}+\frac {21 \log (\cos (c+d x)+1)}{32 a d} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Cot[c + d*x]^5/(a + a*Sec[c + d*x]),x]

[Out]

-1/32*1/(a*d*(1 - Cos[c + d*x])^2) + 1/(4*a*d*(1 - Cos[c + d*x])) + 1/(24*a*d*(1 + Cos[c + d*x])^3) - 9/(32*a*
d*(1 + Cos[c + d*x])^2) + 15/(16*a*d*(1 + Cos[c + d*x])) + (11*Log[1 - Cos[c + d*x]])/(32*a*d) + (21*Log[1 + C
os[c + d*x]])/(32*a*d)

Rule 90

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandI
ntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] &&
(IntegerQ[p] || (GtQ[m, 0] && GeQ[n, -1]))

Rule 3964

Int[cot[(c_.) + (d_.)*(x_)]^(m_.)*(csc[(c_.) + (d_.)*(x_)]*(b_.) + (a_))^(n_.), x_Symbol] :> Dist[1/(a^(m - n
- 1)*b^n*d), Subst[Int[(a - b*x)^((m - 1)/2)*((a + b*x)^((m - 1)/2 + n)/x^(m + n)), x], x, Sin[c + d*x]], x] /
; FreeQ[{a, b, c, d}, x] && IntegerQ[(m - 1)/2] && EqQ[a^2 - b^2, 0] && IntegerQ[n]

Rubi steps

\begin {align*} \int \frac {\cot ^5(c+d x)}{a+a \sec (c+d x)} \, dx &=-\frac {a^6 \text {Subst}\left (\int \frac {x^6}{(a-a x)^3 (a+a x)^4} \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac {a^6 \text {Subst}\left (\int \left (-\frac {1}{16 a^7 (-1+x)^3}-\frac {1}{4 a^7 (-1+x)^2}-\frac {11}{32 a^7 (-1+x)}+\frac {1}{8 a^7 (1+x)^4}-\frac {9}{16 a^7 (1+x)^3}+\frac {15}{16 a^7 (1+x)^2}-\frac {21}{32 a^7 (1+x)}\right ) \, dx,x,\cos (c+d x)\right )}{d}\\ &=-\frac {1}{32 a d (1-\cos (c+d x))^2}+\frac {1}{4 a d (1-\cos (c+d x))}+\frac {1}{24 a d (1+\cos (c+d x))^3}-\frac {9}{32 a d (1+\cos (c+d x))^2}+\frac {15}{16 a d (1+\cos (c+d x))}+\frac {11 \log (1-\cos (c+d x))}{32 a d}+\frac {21 \log (1+\cos (c+d x))}{32 a d}\\ \end {align*}

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Mathematica [A]
time = 0.55, size = 135, normalized size = 0.93 \begin {gather*} -\frac {\cos ^2\left (\frac {1}{2} (c+d x)\right ) \left (-48 \csc ^2\left (\frac {1}{2} (c+d x)\right )+3 \csc ^4\left (\frac {1}{2} (c+d x)\right )-504 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )-264 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )-180 \sec ^2\left (\frac {1}{2} (c+d x)\right )+27 \sec ^4\left (\frac {1}{2} (c+d x)\right )-2 \sec ^6\left (\frac {1}{2} (c+d x)\right )\right ) \sec (c+d x)}{192 a d (1+\sec (c+d x))} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Cot[c + d*x]^5/(a + a*Sec[c + d*x]),x]

[Out]

-1/192*(Cos[(c + d*x)/2]^2*(-48*Csc[(c + d*x)/2]^2 + 3*Csc[(c + d*x)/2]^4 - 504*Log[Cos[(c + d*x)/2]] - 264*Lo
g[Sin[(c + d*x)/2]] - 180*Sec[(c + d*x)/2]^2 + 27*Sec[(c + d*x)/2]^4 - 2*Sec[(c + d*x)/2]^6)*Sec[c + d*x])/(a*
d*(1 + Sec[c + d*x]))

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Maple [A]
time = 0.14, size = 91, normalized size = 0.63

method	result	size
derivativedivides	\(\frac {-\frac {1}{32 \left (-1+\cos \left (d x +c \right )\right )^{2}}-\frac {1}{4 \left (-1+\cos \left (d x +c \right )\right )}+\frac {11 \ln \left (-1+\cos \left (d x +c \right )\right )}{32}+\frac {1}{24 \left (1+\cos \left (d x +c \right )\right )^{3}}-\frac {9}{32 \left (1+\cos \left (d x +c \right )\right )^{2}}+\frac {15}{16 \left (1+\cos \left (d x +c \right )\right )}+\frac {21 \ln \left (1+\cos \left (d x +c \right )\right )}{32}}{d a}\)	\(91\)
default	\(\frac {-\frac {1}{32 \left (-1+\cos \left (d x +c \right )\right )^{2}}-\frac {1}{4 \left (-1+\cos \left (d x +c \right )\right )}+\frac {11 \ln \left (-1+\cos \left (d x +c \right )\right )}{32}+\frac {1}{24 \left (1+\cos \left (d x +c \right )\right )^{3}}-\frac {9}{32 \left (1+\cos \left (d x +c \right )\right )^{2}}+\frac {15}{16 \left (1+\cos \left (d x +c \right )\right )}+\frac {21 \ln \left (1+\cos \left (d x +c \right )\right )}{32}}{d a}\)	\(91\)
risch	\(-\frac {i x}{a}-\frac {2 i c}{a d}+\frac {33 \,{\mathrm e}^{9 i \left (d x +c \right )}-78 \,{\mathrm e}^{8 i \left (d x +c \right )}-184 \,{\mathrm e}^{7 i \left (d x +c \right )}-2 \,{\mathrm e}^{6 i \left (d x +c \right )}+270 \,{\mathrm e}^{5 i \left (d x +c \right )}-2 \,{\mathrm e}^{4 i \left (d x +c \right )}-184 \,{\mathrm e}^{3 i \left (d x +c \right )}-78 \,{\mathrm e}^{2 i \left (d x +c \right )}+33 \,{\mathrm e}^{i \left (d x +c \right )}}{24 d a \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )^{6} \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )^{4}}+\frac {21 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{16 a d}+\frac {11 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{16 a d}\)	\(193\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cot(d*x+c)^5/(a+a*sec(d*x+c)),x,method=_RETURNVERBOSE)

[Out]

1/d/a*(-1/32/(-1+cos(d*x+c))^2-1/4/(-1+cos(d*x+c))+11/32*ln(-1+cos(d*x+c))+1/24/(1+cos(d*x+c))^3-9/32/(1+cos(d
*x+c))^2+15/16/(1+cos(d*x+c))+21/32*ln(1+cos(d*x+c)))

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Maxima [A]
time = 0.28, size = 130, normalized size = 0.90 \begin {gather*} \frac {\frac {2 \, {\left (33 \, \cos \left (d x + c\right )^{4} - 39 \, \cos \left (d x + c\right )^{3} - 79 \, \cos \left (d x + c\right )^{2} + 29 \, \cos \left (d x + c\right ) + 44\right )}}{a \cos \left (d x + c\right )^{5} + a \cos \left (d x + c\right )^{4} - 2 \, a \cos \left (d x + c\right )^{3} - 2 \, a \cos \left (d x + c\right )^{2} + a \cos \left (d x + c\right ) + a} + \frac {63 \, \log \left (\cos \left (d x + c\right ) + 1\right )}{a} + \frac {33 \, \log \left (\cos \left (d x + c\right ) - 1\right )}{a}}{96 \, d} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(d*x+c)^5/(a+a*sec(d*x+c)),x, algorithm="maxima")

[Out]

1/96*(2*(33*cos(d*x + c)^4 - 39*cos(d*x + c)^3 - 79*cos(d*x + c)^2 + 29*cos(d*x + c) + 44)/(a*cos(d*x + c)^5 +
a*cos(d*x + c)^4 - 2*a*cos(d*x + c)^3 - 2*a*cos(d*x + c)^2 + a*cos(d*x + c) + a) + 63*log(cos(d*x + c) + 1)/a
+ 33*log(cos(d*x + c) - 1)/a)/d

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Fricas [A]
time = 3.10, size = 217, normalized size = 1.50 \begin {gather*} \frac {66 \, \cos \left (d x + c\right )^{4} - 78 \, \cos \left (d x + c\right )^{3} - 158 \, \cos \left (d x + c\right )^{2} + 63 \, {\left (\cos \left (d x + c\right )^{5} + \cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{3} - 2 \, \cos \left (d x + c\right )^{2} + \cos \left (d x + c\right ) + 1\right )} \log \left (\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) + 33 \, {\left (\cos \left (d x + c\right )^{5} + \cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{3} - 2 \, \cos \left (d x + c\right )^{2} + \cos \left (d x + c\right ) + 1\right )} \log \left (-\frac {1}{2} \, \cos \left (d x + c\right ) + \frac {1}{2}\right ) + 58 \, \cos \left (d x + c\right ) + 88}{96 \, {\left (a d \cos \left (d x + c\right )^{5} + a d \cos \left (d x + c\right )^{4} - 2 \, a d \cos \left (d x + c\right )^{3} - 2 \, a d \cos \left (d x + c\right )^{2} + a d \cos \left (d x + c\right ) + a d\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(d*x+c)^5/(a+a*sec(d*x+c)),x, algorithm="fricas")

[Out]

1/96*(66*cos(d*x + c)^4 - 78*cos(d*x + c)^3 - 158*cos(d*x + c)^2 + 63*(cos(d*x + c)^5 + cos(d*x + c)^4 - 2*cos
(d*x + c)^3 - 2*cos(d*x + c)^2 + cos(d*x + c) + 1)*log(1/2*cos(d*x + c) + 1/2) + 33*(cos(d*x + c)^5 + cos(d*x
+ c)^4 - 2*cos(d*x + c)^3 - 2*cos(d*x + c)^2 + cos(d*x + c) + 1)*log(-1/2*cos(d*x + c) + 1/2) + 58*cos(d*x + c
) + 88)/(a*d*cos(d*x + c)^5 + a*d*cos(d*x + c)^4 - 2*a*d*cos(d*x + c)^3 - 2*a*d*cos(d*x + c)^2 + a*d*cos(d*x +
c) + a*d)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \frac {\int \frac {\cot ^{5}{\left (c + d x \right )}}{\sec {\left (c + d x \right )} + 1}\, dx}{a} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(d*x+c)**5/(a+a*sec(d*x+c)),x)

[Out]

Integral(cot(c + d*x)**5/(sec(c + d*x) + 1), x)/a

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Giac [A]
time = 0.52, size = 211, normalized size = 1.46 \begin {gather*} -\frac {\frac {3 \, {\left (\frac {14 \, {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} + \frac {66 \, {\left (\cos \left (d x + c\right ) - 1\right )}^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + 1\right )} {\left (\cos \left (d x + c\right ) + 1\right )}^{2}}{a {\left (\cos \left (d x + c\right ) - 1\right )}^{2}} - \frac {132 \, \log \left (\frac {{\left | -\cos \left (d x + c\right ) + 1 \right |}}{{\left | \cos \left (d x + c\right ) + 1 \right |}}\right )}{a} + \frac {384 \, \log \left ({\left | -\frac {\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1} + 1 \right |}\right )}{a} + \frac {\frac {132 \, a^{2} {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} + \frac {21 \, a^{2} {\left (\cos \left (d x + c\right ) - 1\right )}^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {2 \, a^{2} {\left (\cos \left (d x + c\right ) - 1\right )}^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}}}{a^{3}}}{384 \, d} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cot(d*x+c)^5/(a+a*sec(d*x+c)),x, algorithm="giac")

[Out]

-1/384*(3*(14*(cos(d*x + c) - 1)/(cos(d*x + c) + 1) + 66*(cos(d*x + c) - 1)^2/(cos(d*x + c) + 1)^2 + 1)*(cos(d
*x + c) + 1)^2/(a*(cos(d*x + c) - 1)^2) - 132*log(abs(-cos(d*x + c) + 1)/abs(cos(d*x + c) + 1))/a + 384*log(ab
s(-(cos(d*x + c) - 1)/(cos(d*x + c) + 1) + 1))/a + (132*a^2*(cos(d*x + c) - 1)/(cos(d*x + c) + 1) + 21*a^2*(co
s(d*x + c) - 1)^2/(cos(d*x + c) + 1)^2 + 2*a^2*(cos(d*x + c) - 1)^3/(cos(d*x + c) + 1)^3)/a^3)/d

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Mupad [B]
time = 1.31, size = 132, normalized size = 0.91 \begin {gather*} \frac {11\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{32\,a\,d}-\frac {7\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{128\,a\,d}+\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6}{192\,a\,d}+\frac {11\,\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{16\,a\,d}-\frac {\ln \left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}{a\,d}+\frac {{\mathrm {cot}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (\frac {7\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{2}-\frac {1}{4}\right )}{32\,a\,d} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cot(c + d*x)^5/(a + a/cos(c + d*x)),x)

[Out]

(11*tan(c/2 + (d*x)/2)^2)/(32*a*d) - (7*tan(c/2 + (d*x)/2)^4)/(128*a*d) + tan(c/2 + (d*x)/2)^6/(192*a*d) + (11
*log(tan(c/2 + (d*x)/2)))/(16*a*d) - log(tan(c/2 + (d*x)/2)^2 + 1)/(a*d) + (cot(c/2 + (d*x)/2)^4*((7*tan(c/2 +
(d*x)/2)^2)/2 - 1/4))/(32*a*d)

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